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General
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3. The segment of DNA shown in Figure 19.1 below has restriction
sites I and
II, which create restriction fragments A, B, and C. Which of the gels
produced by electrophoresis and shown below (Fig. 19.2) would represent
the separation and identity of these fragments? (See text Figs. 20.7
& 20.8. For overview, click here.
b. 2
c. 3
d. 4
e. 5
4. It is theoretically possible to transfer a gene from any organism
to
any other organism. Why is this possible?
a. All organisms use the same genetic code.
b. All organisms are made up of cells.
c. All organisms have similar nuclei.
d. All organisms have ribosomes.
e. All organisms have transfer RNA.
5. The polymerase chain reaction is important because it allows
us to
a. insert eukaryotic genes into prokaryotic
plasmids.
b. incorporate genes into viruses.
c. make DNA from RNA transcripts.
d. make many copies of a DNA sample.
e. insert regulatory sequences into eukaryotic
genes.
------------------------------
Use the choices shown below to answer the following question(s).
Each choice may be used once, more than once, or not at all.
1. restriction
enzymes
2. DNA ligase
3. reverse transcriptase
4. RNA polymerase
5. DNA polymerase
6. Which enzyme permanently seals together DNA fragments that
have
complementary sticky ends?
a. 1
b. 2
c. 3
d. 4
e. 5
7. Which enzyme is used to make complementary DNA (cDNA)?
a. 1
b. 2
c. 3
d. 4
e. 5
9. Which enzyme is used to make multiple copies of genes in the
polymerase chain reaction (PCR)?
a. 1
b. 2
c. 3
d. 4
e. 5
10. Which enzyme is used to produce RFLP fragments?
a. 1
b. 2
c. 3
d. 4
e. 5
12. Which of the following procedures would produce RFLPs?
a. incubating a mixture of single-strand DNA
from two closely
related species
b. incubating DNA nucleotides with DNA polymerase
c. incubating DNA with restriction enzymes
(restriction endonucleases)
d. incubating RNA with DNA nucleotides and
reverse transcriptase
e. incubating DNA fragments with "sticky ends"
with ligase
13. If you discovered a bacterial cell that contained no restriction
endonuclease, which of the following would
you expect to happen?
1. The
cell would be unable to replicate its DNA.
2. The
cell would create incomplete plasmids.
3. The
cell would be easily infected and lysed by
bacteriophages.
4. The
cell would become an obligate parasite.
a. 1
b. 2
c. 3
d. 4
e. Both 1 and 4 would occur.
------------------------------
Use the following information and Figure 19.3 to answer the
question(s). The DNA fingerprints above represent four different
individuals.
18. Which of the following statements is consistent with the results?
a. B is the child of A and C.
b. C is the child of A and B.
c. D is the child of B and C.
d. A is the child of B and C.
e. A is the child of C and D.
19. Which of the following statements is most likely TRUE?
a. D is the child of A and C.
b. D is the child of A and B.
c. D is the child of B and C.
d. A is the child of C and D.
e. B is the child of A and C.
21. A DNA fingerprint was produced by
1. treating
selected segments of DNA with restriction enzymes.
2. electrophoresis
of restriction fragments.
3. oligonucleotides
from PCRs.
4. electroporation
of cDNAs.
a. 1
b. 2
c. 3
d. 4
e. Both 1 and 2 are correct.
------------------------------
26. Why is it difficult to get bacteria to express genes directly
from
eukaryotic DNA?
a. Eukaryotic genes are not transcribed in
a single transcript.
b. Eukaryotic genes do not contain enhancer
sequences.
c. Eukaryotic genes contain introns.
d. Eukaryotic genes lack controlling regions.
e. Eukaryotic genes may contain transposons.
27. Reverse transcriptase is important in genetic engineering
because
1. it is found
in retroviruses.
2. it allows
us to make DNA from RNA.
3. it allows
bacteria to translate eukaryotic RNA.
4. it removes
exons from eukaryotic genes.
a. 1
b. 2
c. 3
d. 4
e. Both 3 and 4 are correct.
------------------------------
41. Which of the following is the most logical sequence of the
steps
shown below for splicing foreign DNA into
a plasmid and inserting
the plasmid into a bacterium?
I.
transform E. coli cells
II.
cleave or cut the plasmid with the same endonuclease use to cut out the
gene
III.
extract plasmid DNA from bacterial cells
IV.
join plasmid DNA with foreign DNA by hydrogen bonds
V.
seal with DNA ligase
a. I, II, IV, III, V
b. II, III, V, IV, I
c. III, II, IV, V, I
d. III, IV, V, I, II
e. IV, V, I, II, III
46. The principal problem with inserting an unmodified mammalian
gene
into the bacterial chromosome, and then getting
that gene expressed,
is that
a. prokaryotes use a different genetic code
from that of eukaryotes.
b. bacteria translate polycistronic messages
only.
c. bacteria cannot remove eukaryotic introns.
d. bacterial RNA polymerase cannot make RNA
complementary to
mammalian DNA.
e. bacterial DNA is not found in a membrane-bound
nucleus and is
therefore incompatible with
mammalian DNA.
48. A DNA gene that contains introns can be made shorter (but
remain
functional) for genetic engineering purposes
by
a. using RNA polymerase to transcribe the
gene.
b. using a restriction endonuclease to cut
the gene into shorter
pieces.
c. using reverse transcriptase to reconstruct
the gene from its
mRNA.
d. using DNA polymerase to reconstruct the
gene from its polypeptide
product.
e. using DNA ligase to put together fragments
of the DNA that codes
for a particular polypeptide.
Ch. 20, DNA Technology, ANSWER KEY MT
The 19's below refer to a previous edition of the
textbook.
+--------+--------+--------+--------+--------+--------+--------+
| Text | Exam |
| Ques | Dif | Text |
|Chapter Question| Answer | Cat | Cat
| Page |
+--------+--------+--------+--------+--------+--------+--------+
| 20 1
1 d
|
| 19 2
2 e
|
| 19 3
3 b
|
| 19 4
4 a
|
| 19 5
5 d
|
| 19 6
6 b
|
| 19 7
7 c
|
| 19 8
8 d
|
| 19 9
9 e
|
| 19 10
10 a
|
| 19 11
11 a
|
| 19 12
12 c
|
| 19 13
13 c
|
| 19 14
14 e
|
| 19 15
15 d
|
| 19 16
16 d
|
| 19 17
17 a
|
| 19 18
18 b
|
| 19 19
19 b
|
| 19 20
20 d
|
| 19 21
21 e
|
| 19 22
22 c
|
| 19 23
23 b
|
| 19 24
24 d
|
| 19 25
25 e
|
| 19 26
26 c
|
| 19 27
27 b
|
| 19 28
28 c
|
| 19 29
29 b
|
| 19 30
30 e
|
| 19 31
31 d
|
| 19 32
32 c
|
| 19 33
33 c
|
| 19 34
34 c
|
| 19 35
35 d
|
| 19 36
36 c
|
| 19 37
37 c
|
| 19 38
38 a
|
| 19 39
39 d
|
| 19 40
40 a
|
| 19 41
41 c
|
| 19 42
42 d
|
| 19 43
43 b
|
| 19 44
44 c
|
| 19 45
45 d
|
| 19 46
46 c
|
| 19 47
47 c
|
| 19 48
48 c
|
| 19 49
49 d
|
| 19 50
50 e
|
| 19 51
51 d
|
| 19 52
52 a
|
| 19 53
53 d
|
| 19 54
54 d
|
| 19 55
55 e
|
| 19 56
56 b
|
| 19 57
57 e
|
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